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Theorem bj-nnfbid 34082
Description: Nonfreeness in both sides implies nonfreeness in the biconditional, deduction form. (Contributed by BJ, 2-Dec-2023.) (Proof modification is discouraged.)
Hypotheses
Ref Expression
bj-nnfbid.1 (𝜑 → Ⅎ'𝑥𝜓)
bj-nnfbid.2 (𝜑 → Ⅎ'𝑥𝜒)
Assertion
Ref Expression
bj-nnfbid (𝜑 → Ⅎ'𝑥(𝜓𝜒))

Proof of Theorem bj-nnfbid
StepHypRef Expression
1 bj-nnfbid.1 . . . 4 (𝜑 → Ⅎ'𝑥𝜓)
2 bj-nnfbid.2 . . . 4 (𝜑 → Ⅎ'𝑥𝜒)
3 bj-nnfim 34075 . . . 4 ((Ⅎ'𝑥𝜓 ∧ Ⅎ'𝑥𝜒) → Ⅎ'𝑥(𝜓𝜒))
41, 2, 3syl2anc 586 . . 3 (𝜑 → Ⅎ'𝑥(𝜓𝜒))
5 bj-nnfim 34075 . . . 4 ((Ⅎ'𝑥𝜒 ∧ Ⅎ'𝑥𝜓) → Ⅎ'𝑥(𝜒𝜓))
62, 1, 5syl2anc 586 . . 3 (𝜑 → Ⅎ'𝑥(𝜒𝜓))
74, 6bj-nnfand 34078 . 2 (𝜑 → Ⅎ'𝑥((𝜓𝜒) ∧ (𝜒𝜓)))
8 dfbi2 477 . . 3 ((𝜓𝜒) ↔ ((𝜓𝜒) ∧ (𝜒𝜓)))
98bj-nnfbii 34059 . 2 (Ⅎ'𝑥(𝜓𝜒) ↔ Ⅎ'𝑥((𝜓𝜒) ∧ (𝜒𝜓)))
107, 9sylibr 236 1 (𝜑 → Ⅎ'𝑥(𝜓𝜒))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 208  wa 398  Ⅎ'wnnf 34055
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810
This theorem depends on definitions:  df-bi 209  df-an 399  df-ex 1781  df-bj-nnf 34056
This theorem is referenced by: (None)
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