Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
||
Mirrors > Home > MPE Home > Th. List > equsb3rOLD | Structured version Visualization version GIF version |
Description: Obsolete version of equsb3r 2110 as of 2-Sep-2023. (Contributed by AV, 29-Jul-2023.) (Proof modification is discouraged.) (New usage is discouraged.) |
Ref | Expression |
---|---|
equsb3rOLD | ⊢ ([𝑦 / 𝑥]𝑧 = 𝑥 ↔ 𝑧 = 𝑦) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | equcom 2025 | . . 3 ⊢ (𝑧 = 𝑥 ↔ 𝑥 = 𝑧) | |
2 | 1 | sbbii 2081 | . 2 ⊢ ([𝑦 / 𝑥]𝑧 = 𝑥 ↔ [𝑦 / 𝑥]𝑥 = 𝑧) |
3 | equsb3 2109 | . 2 ⊢ ([𝑦 / 𝑥]𝑥 = 𝑧 ↔ 𝑦 = 𝑧) | |
4 | equcom 2025 | . 2 ⊢ (𝑦 = 𝑧 ↔ 𝑧 = 𝑦) | |
5 | 2, 3, 4 | 3bitri 299 | 1 ⊢ ([𝑦 / 𝑥]𝑧 = 𝑥 ↔ 𝑧 = 𝑦) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 208 [wsb 2069 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-5 1911 ax-6 1970 ax-7 2015 |
This theorem depends on definitions: df-bi 209 df-an 399 df-ex 1781 df-sb 2070 |
This theorem is referenced by: (None) |
Copyright terms: Public domain | W3C validator |