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| Description: Step 15 of Meredith's proof of Lukasiewicz axioms from his sole axiom. (Contributed by NM, 22-Dec-2002.) (Proof modification is discouraged.) (New usage is discouraged.) | 
| Ref | Expression | 
|---|---|
| merlem8 | ⊢ (((𝜓 → 𝜒) → 𝜃) → (((𝜒 → 𝜏) → (¬ 𝜃 → ¬ 𝜓)) → 𝜃)) | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | meredith 1640 | . 2 ⊢ (((((𝜑 → 𝜑) → (¬ 𝜑 → ¬ 𝜑)) → 𝜑) → 𝜑) → ((𝜑 → 𝜑) → (𝜑 → 𝜑))) | |
| 2 | merlem7 1647 | . 2 ⊢ ((((((𝜑 → 𝜑) → (¬ 𝜑 → ¬ 𝜑)) → 𝜑) → 𝜑) → ((𝜑 → 𝜑) → (𝜑 → 𝜑))) → (((𝜓 → 𝜒) → 𝜃) → (((𝜒 → 𝜏) → (¬ 𝜃 → ¬ 𝜓)) → 𝜃))) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ (((𝜓 → 𝜒) → 𝜃) → (((𝜒 → 𝜏) → (¬ 𝜃 → ¬ 𝜓)) → 𝜃)) | 
| Colors of variables: wff setvar class | 
| Syntax hints: ¬ wn 3 → wi 4 | 
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 | 
| This theorem is referenced by: merlem9 1649 | 
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