Theorem imdistanda 674

Description: Distribution of implication with conjunction (deduction version with conjoined antecedent). (Contributed by Jeff Madsen, 19-Jun-2011.)

Hypothesis

Ref	Expression
imdistanda.1	|- ((ph /\ ps) -> (ch -> th))

Assertion

Ref	Expression
imdistanda	|- (ph -> ((ps /\ ch) -> (ps /\ th)))

Proof of Theorem imdistanda

Step	Hyp	Ref	Expression
1		imdistanda.1	. . 3 |- ((ph /\ ps) -> (ch -> th))
2	1	ex 423	. 2 |- (ph -> (ps -> (ch -> th)))
3	2	imdistand 673	1 |- (ph -> ((ps /\ ch) -> (ps /\ th)))

This proof depends on syntax axioms:   -> wi 4   /\ wa 358

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This proof depends on definitions:  df-bi 177  df-an 360

This theorem is used by: (None)