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Theorem pm5.21ndd 631
Description: Eliminate an antecedent implied by each side of a biconditional, deduction version. (Contributed by Paul Chapman, 21-Nov-2012.) (Revised by Mario Carneiro, 31-Jan-2015.)
Hypotheses
Ref Expression
pm5.21ndd.1 (𝜑 → (𝜒𝜓))
pm5.21ndd.2 (𝜑 → (𝜃𝜓))
pm5.21ndd.3 (𝜑 → (𝜓 → (𝜒𝜃)))
Assertion
Ref Expression
pm5.21ndd (𝜑 → (𝜒𝜃))

Proof of Theorem pm5.21ndd
StepHypRef Expression
1 pm5.21ndd.1 . . . 4 (𝜑 → (𝜒𝜓))
2 pm5.21ndd.3 . . . 4 (𝜑 → (𝜓 → (𝜒𝜃)))
31, 2syld 44 . . 3 (𝜑 → (𝜒 → (𝜒𝜃)))
43ibd 171 . 2 (𝜑 → (𝜒𝜃))
5 pm5.21ndd.2 . . . . 5 (𝜑 → (𝜃𝜓))
65, 2syld 44 . . . 4 (𝜑 → (𝜃 → (𝜒𝜃)))
7 bicom1 126 . . . 4 ((𝜒𝜃) → (𝜃𝜒))
86, 7syl6 33 . . 3 (𝜑 → (𝜃 → (𝜃𝜒)))
98ibd 171 . 2 (𝜑 → (𝜃𝜒))
104, 9impbid 124 1 (𝜑 → (𝜒𝜃))
Colors of variables: wff set class
Syntax hints:  wi 4  wb 102
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 103  ax-ia2 104  ax-ia3 105
This theorem depends on definitions:  df-bi 114
This theorem is referenced by:  pm5.21nd  836  sbcrext  2863  rmob  2878  epelg  4055  eqbrrdva  4533  relbrcnvg  4732  fmptco  5358  ovelrn  5677  brtpos2  5897  brdomg  6260  genpelvl  6668  genpelvu  6669  fzoval  9107  clim  10033
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