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Theorem sb5fALT 2603
Description: Alternate version of sb5f 2538. (Contributed by NM, 5-Aug-1993.) (Revised by Mario Carneiro, 4-Oct-2016.) (Proof modification is discouraged.) (New usage is discouraged.)
Hypotheses
Ref Expression
dfsb1.p5 (𝜃 ↔ ((𝑥 = 𝑦𝜑) ∧ ∃𝑥(𝑥 = 𝑦𝜑)))
sb6fALT.1 𝑦𝜑
Assertion
Ref Expression
sb5fALT (𝜃 ↔ ∃𝑥(𝑥 = 𝑦𝜑))

Proof of Theorem sb5fALT
StepHypRef Expression
1 dfsb1.p5 . . 3 (𝜃 ↔ ((𝑥 = 𝑦𝜑) ∧ ∃𝑥(𝑥 = 𝑦𝜑)))
2 sb6fALT.1 . . 3 𝑦𝜑
31, 2sb6fALT 2602 . 2 (𝜃 ↔ ∀𝑥(𝑥 = 𝑦𝜑))
42equs45f 2482 . 2 (∃𝑥(𝑥 = 𝑦𝜑) ↔ ∀𝑥(𝑥 = 𝑦𝜑))
53, 4bitr4i 280 1 (𝜃 ↔ ∃𝑥(𝑥 = 𝑦𝜑))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 208  wa 398  wal 1535  wex 1780  wnf 1784
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-10 2145  ax-12 2177  ax-13 2390
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-ex 1781  df-nf 1785
This theorem is referenced by:  sb7fALT  2616
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