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Mirrors > Home > QLE Home > Th. List > lem3a.1 | GIF version |
Description: Lemma used in proof of Thm. 3.1 of Pavicic 1993. (Contributed by NM, 12-Aug-1997.) |
Ref | Expression |
---|---|
lem3.1.1 | (a ∪ b) = b |
lem3.1.2 | (b⊥ ∪ a) = 1 |
Ref | Expression |
---|---|
lem3a.1 | (a ∪ b) = a |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | lem3.1.1 | . . . . 5 (a ∪ b) = b | |
2 | lem3.1.2 | . . . . 5 (b⊥ ∪ a) = 1 | |
3 | 1, 2 | lem3.1 443 | . . . 4 a = b |
4 | 3 | ax-r1 35 | . . 3 b = a |
5 | 4 | lor 70 | . 2 (a ∪ b) = (a ∪ a) |
6 | oridm 110 | . 2 (a ∪ a) = a | |
7 | 5, 6 | ax-r2 36 | 1 (a ∪ b) = a |
Colors of variables: term |
Syntax hints: = wb 1 ⊥ wn 4 ∪ wo 6 1wt 8 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 ax-r3 439 |
This theorem depends on definitions: df-b 39 df-a 40 df-t 41 df-f 42 |
This theorem is referenced by: (None) |
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