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| Mirrors > Home > QLE Home > Th. List > nom10 | GIF version | ||
| Description: Part of Lemma 3.3(14) from "Non-Orthomodular Models..." paper. (Contributed by NM, 7-Feb-1999.) |
| Ref | Expression |
|---|---|
| nom10 | (a →0 (a ∩ b)) = (a →1 b) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | id 59 | . 2 (a⊥ ∪ (a ∩ b)) = (a⊥ ∪ (a ∩ b)) | |
| 2 | df-i0 43 | . 2 (a →0 (a ∩ b)) = (a⊥ ∪ (a ∩ b)) | |
| 3 | df-i1 44 | . 2 (a →1 b) = (a⊥ ∪ (a ∩ b)) | |
| 4 | 1, 2, 3 | 3tr1 63 | 1 (a →0 (a ∩ b)) = (a →1 b) |
| Colors of variables: term |
| Syntax hints: = wb 1 ⊥ wn 4 ∪ wo 6 ∩ wa 7 →0 wi0 11 →1 wi1 12 |
| This theorem was proved from axioms: ax-a1 30 ax-r1 35 ax-r2 36 |
| This theorem depends on definitions: df-i0 43 df-i1 44 |
| This theorem is referenced by: nom40 325 lem3.3.7i0e3 1059 |
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