Theorem sseqtrd 3036

Description: Substitution of equality into a subclass relationship. (Contributed by NM, 25-Apr-2004.)

Hypotheses

Ref	Expression
sseqtrd.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
sseqtrd.2	⊢ (𝜑 → 𝐵 = 𝐶)

Assertion

Ref	Expression
sseqtrd	⊢ (𝜑 → 𝐴 ⊆ 𝐶)

Proof of Theorem sseqtrd

Step	Hyp	Ref	Expression
1		sseqtrd.1	. 2 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
2		sseqtrd.2	. . 3 ⊢ (𝜑 → 𝐵 = 𝐶)
3	2	sseq2d 3028	. 2 ⊢ (𝜑 → (𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ 𝐶))
4	1, 3	mpbid 145	1 ⊢ (𝜑 → 𝐴 ⊆ 𝐶)

Syntax hints:   → wi 4   = wceq 1285   ⊆ wss 2974

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-5 1377  ax-7 1378  ax-gen 1379  ax-ie1 1423  ax-ie2 1424  ax-8 1436  ax-11 1438  ax-4 1441  ax-17 1460  ax-i9 1464  ax-ial 1468  ax-i5r 1469  ax-ext 2064

This theorem depends on definitions:  df-bi 115  df-nf 1391  df-sb 1687  df-clab 2069  df-cleq 2075  df-clel 2078  df-in 2980  df-ss 2987

This theorem is referenced by:  sseqtr4d  3037  resasplitss  5100  nnaword2  6153  erssxp  6195  phpm  6400  ioodisj  9091