Proof of Theorem dfsb2
| Step | Hyp | Ref
| Expression |
| 1 | | sbequ2 1177 |
. . . . . 6
⊢ (x =
y → ([y / x]φ → φ)) |
| 2 | 1 | a4s 982 |
. . . . 5
⊢ (∀x x = y → ([y /
x]φ
→ φ)) |
| 3 | | ax-4 971 |
. . . . 5
⊢ (∀x x = y → x =
y) |
| 4 | 2, 3 | jctild 600 |
. . . 4
⊢ (∀x x = y → ([y /
x]φ
→ (x = y ⋀ φ))) |
| 5 | | orc 269 |
. . . 4
⊢ ((x =
y ⋀ φ) → ((x = y ⋀
φ) ⋁ ∀x(x = y → φ))) |
| 6 | 4, 5 | syl6 22 |
. . 3
⊢ (∀x x = y → ([y /
x]φ
→ ((x = y ⋀ φ)
⋁ ∀x(x = y →
φ)))) |
| 7 | | sb4 1221 |
. . . 4
⊢ (¬ ∀x x = y → ([y /
x]φ
→ ∀x(x = y →
φ))) |
| 8 | | olc 268 |
. . . 4
⊢ (∀x(x = y → φ)
→ ((x = y ⋀ φ)
⋁ ∀x(x = y →
φ))) |
| 9 | 7, 8 | syl6 22 |
. . 3
⊢ (¬ ∀x x = y → ([y /
x]φ
→ ((x = y ⋀ φ)
⋁ ∀x(x = y →
φ)))) |
| 10 | 6, 9 | pm2.61i 126 |
. 2
⊢ ([y /
x]φ
→ ((x = y ⋀ φ)
⋁ ∀x(x = y →
φ))) |
| 11 | | sbequ1 1176 |
. . . 4
⊢ (x =
y → (φ → [y / x]φ)) |
| 12 | 11 | imp 350 |
. . 3
⊢ ((x =
y ⋀ φ) → [y / x]φ) |
| 13 | | sb2 1175 |
. . 3
⊢ (∀x(x = y → φ)
→ [y / x]φ) |
| 14 | 12, 13 | jaoi 341 |
. 2
⊢ (((x =
y ⋀ φ) ⋁ ∀x(x = y → φ))
→ [y / x]φ) |
| 15 | 10, 14 | impbi 157 |
1
⊢ ([y /
x]φ
↔ ((x = y ⋀ φ)
⋁ ∀x(x = y →
φ))) |