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| Mirrors > Home > ILE Home > Th. List > anbi1cd | GIF version | ||
| Description: Introduce a proposition as left conjunct on the left-hand side and right conjunct on the right-hand side of an equivalence. Deduction form. (Contributed by Peter Mazsa, 22-May-2021.) |
| Ref | Expression |
|---|---|
| anbi1cd.1 | ⊢ (𝜑 → (𝜓 ↔ 𝜒)) |
| Ref | Expression |
|---|---|
| anbi1cd | ⊢ (𝜑 → ((𝜃 ∧ 𝜓) ↔ (𝜒 ∧ 𝜃))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | anbi1cd.1 | . . 3 ⊢ (𝜑 → (𝜓 ↔ 𝜒)) | |
| 2 | 1 | anbi2d 464 | . 2 ⊢ (𝜑 → ((𝜃 ∧ 𝜓) ↔ (𝜃 ∧ 𝜒))) |
| 3 | 2 | biancomd 271 | 1 ⊢ (𝜑 → ((𝜃 ∧ 𝜓) ↔ (𝜒 ∧ 𝜃))) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ∧ wa 104 ↔ wb 105 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 |
| This theorem depends on definitions: df-bi 117 |
| This theorem is referenced by: (None) |
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