Theorem bdbi 13708

Description: A biconditional between two bounded formulas is bounded. (Contributed by BJ, 3-Oct-2019.)

Hypotheses

Ref	Expression
bdbi.1	⊢ BOUNDED 𝜑
bdbi.2	⊢ BOUNDED 𝜓

Assertion

Ref	Expression
bdbi	⊢ BOUNDED (𝜑 ↔ 𝜓)

Proof of Theorem bdbi

Step	Hyp	Ref	Expression
1		bdbi.1	. . . 4 ⊢ BOUNDED 𝜑
2		bdbi.2	. . . 4 ⊢ BOUNDED 𝜓
3	1, 2	ax-bdim 13696	. . 3 ⊢ BOUNDED (𝜑 → 𝜓)
4	2, 1	ax-bdim 13696	. . 3 ⊢ BOUNDED (𝜓 → 𝜑)
5	3, 4	ax-bdan 13697	. 2 ⊢ BOUNDED ((𝜑 → 𝜓) ∧ (𝜓 → 𝜑))
6		dfbi2 386	. 2 ⊢ ((𝜑 ↔ 𝜓) ↔ ((𝜑 → 𝜓) ∧ (𝜓 → 𝜑)))
7	5, 6	bd0r 13707	1 ⊢ BOUNDED (𝜑 ↔ 𝜓)

Syntax hints:   → wi 4   ∧ wa 103   ↔ wb 104  BOUNDED wbd 13694

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-bd0 13695  ax-bdim 13696  ax-bdan 13697

This theorem depends on definitions:  df-bi 116

This theorem is referenced by: (None)