Theorem falanfal 1394

Description: A ∧ identity. (Contributed by Anthony Hart, 22-Oct-2010.)

Assertion

Ref	Expression
falanfal	⊢ ((⊥ ∧ ⊥) ↔ ⊥)

Proof of Theorem falanfal

Step	Hyp	Ref	Expression
1		anidm 394	1 ⊢ ((⊥ ∧ ⊥) ↔ ⊥)

Syntax hints:   ∧ wa 103   ↔ wb 104  ⊥wfal 1348

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107

This theorem depends on definitions:  df-bi 116

This theorem is referenced by: (None)