Theorem falorfal 1369

Description: A ∨ identity. (Contributed by Anthony Hart, 22-Oct-2010.) (Proof shortened by Andrew Salmon, 13-May-2011.)

Assertion

Ref	Expression
falorfal	⊢ ((⊥ ∨ ⊥) ↔ ⊥)

Proof of Theorem falorfal

Step	Hyp	Ref	Expression
1		oridm 729	1 ⊢ ((⊥ ∨ ⊥) ↔ ⊥)

Syntax hints:   ↔ wb 104   ∨ wo 680  ⊥wfal 1319

This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 681

This theorem depends on definitions:  df-bi 116

This theorem is referenced by: (None)