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Mirrors > Home > ILE Home > Th. List > imim21b | GIF version |
Description: Simplify an implication between two implications when the antecedent of the first is a consequence of the antecedent of the second. The reverse form is useful in producing the successor step in induction proofs. (Contributed by Paul Chapman, 22-Jun-2011.) (Proof shortened by Wolf Lammen, 14-Sep-2013.) |
Ref | Expression |
---|---|
imim21b | ⊢ ((𝜓 → 𝜑) → (((𝜑 → 𝜒) → (𝜓 → 𝜃)) ↔ (𝜓 → (𝜒 → 𝜃)))) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | bi2.04 247 | . 2 ⊢ (((𝜑 → 𝜒) → (𝜓 → 𝜃)) ↔ (𝜓 → ((𝜑 → 𝜒) → 𝜃))) | |
2 | pm5.5 241 | . . . . 5 ⊢ (𝜑 → ((𝜑 → 𝜒) ↔ 𝜒)) | |
3 | 2 | imbi1d 230 | . . . 4 ⊢ (𝜑 → (((𝜑 → 𝜒) → 𝜃) ↔ (𝜒 → 𝜃))) |
4 | 3 | imim2i 12 | . . 3 ⊢ ((𝜓 → 𝜑) → (𝜓 → (((𝜑 → 𝜒) → 𝜃) ↔ (𝜒 → 𝜃)))) |
5 | 4 | pm5.74d 181 | . 2 ⊢ ((𝜓 → 𝜑) → ((𝜓 → ((𝜑 → 𝜒) → 𝜃)) ↔ (𝜓 → (𝜒 → 𝜃)))) |
6 | 1, 5 | syl5bb 191 | 1 ⊢ ((𝜓 → 𝜑) → (((𝜑 → 𝜒) → (𝜓 → 𝜃)) ↔ (𝜓 → (𝜒 → 𝜃)))) |
Colors of variables: wff set class |
Syntax hints: → wi 4 ↔ wb 104 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 |
This theorem depends on definitions: df-bi 116 |
This theorem is referenced by: (None) |
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