Theorem mpnanrd 697

Description: Eliminate the right side of a negated conjunction in an implication. (Contributed by ML, 17-Oct-2020.)

Hypotheses

Ref	Expression
mpnanrd.1	⊢ (𝜑 → 𝜓)
mpnanrd.2	⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒))

Assertion

Ref	Expression
mpnanrd	⊢ (𝜑 → ¬ 𝜒)

Proof of Theorem mpnanrd

Step	Hyp	Ref	Expression
1		mpnanrd.1	. 2 ⊢ (𝜑 → 𝜓)
2		mpnanrd.2	. . 3 ⊢ (𝜑 → ¬ (𝜓 ∧ 𝜒))
3		imnan 694	. . 3 ⊢ ((𝜓 → ¬ 𝜒) ↔ ¬ (𝜓 ∧ 𝜒))
4	2, 3	sylibr 134	. 2 ⊢ (𝜑 → (𝜓 → ¬ 𝜒))
5	1, 4	mpd 13	1 ⊢ (𝜑 → ¬ 𝜒)

Syntax hints:  ¬ wn 3   → wi 4   ∧ wa 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 617  ax-in2 618

This theorem depends on definitions:  df-bi 117

This theorem is referenced by:  ecase2d  1385