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| Mirrors > Home > MPE Home > Th. List > Mathboxes > alsd | Structured version Visualization version GIF version | ||
| Description: Introduction rule: "all some" holds if the "for all" part holds and the antecedent has a witness. This is the converse of als1d 50451 and als2d 50452 taken together, and is what lets an "all some" statement be proved rather than merely taken apart. (Contributed by David A. Wheeler, 12-Jul-2026.) |
| Ref | Expression |
|---|---|
| alsd.1 | ⊢ (𝜑 → ∀𝑥(𝜓 → 𝜒)) |
| alsd.2 | ⊢ (𝜑 → ∃𝑥𝜓) |
| Ref | Expression |
|---|---|
| alsd | ⊢ (𝜑 → ∀∃𝑥(𝜓 → 𝜒)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | alsd.1 | . 2 ⊢ (𝜑 → ∀𝑥(𝜓 → 𝜒)) | |
| 2 | alsd.2 | . 2 ⊢ (𝜑 → ∃𝑥𝜓) | |
| 3 | df-als 50446 | . 2 ⊢ (∀∃𝑥(𝜓 → 𝜒) ↔ (∀𝑥(𝜓 → 𝜒) ∧ ∃𝑥𝜓)) | |
| 4 | 1, 2, 3 | sylanbrc 594 | 1 ⊢ (𝜑 → ∀∃𝑥(𝜓 → 𝜒)) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ∀wal 1565 ∃wex 1806 ∀∃wals 50444 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-als 50446 |
| This theorem is referenced by: (None) |
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