Theorem nanbi12i 1498

Description: Join two logical equivalences with anti-conjunction. (Contributed by SF, 2-Jan-2018.)

Hypotheses

Ref	Expression
nanbii.1	⊢ (𝜑 ↔ 𝜓)
nanbi12i.2	⊢ (𝜒 ↔ 𝜃)

Assertion

Ref	Expression
nanbi12i	⊢ ((𝜑 ⊼ 𝜒) ↔ (𝜓 ⊼ 𝜃))

Proof of Theorem nanbi12i

Step	Hyp	Ref	Expression
1		nanbii.1	. 2 ⊢ (𝜑 ↔ 𝜓)
2		nanbi12i.2	. 2 ⊢ (𝜒 ↔ 𝜃)
3		nanbi12 1495	. 2 ⊢ (((𝜑 ↔ 𝜓) ∧ (𝜒 ↔ 𝜃)) → ((𝜑 ⊼ 𝜒) ↔ (𝜓 ⊼ 𝜃)))
4	1, 2, 3	mp2an 688	1 ⊢ ((𝜑 ⊼ 𝜒) ↔ (𝜓 ⊼ 𝜃))

Syntax hints:   ↔ wb 205   ⊼ wnan 1483

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 206  df-an 396  df-nan 1484

This theorem is referenced by: (None)