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Mirrors > Home > NFE Home > Th. List > nfbidf | Unicode version |
Description: An equality theorem for effectively not free. (Contributed by Mario Carneiro, 4-Oct-2016.) |
Ref | Expression |
---|---|
nfbidf.1 | |
nfbidf.2 |
Ref | Expression |
---|---|
nfbidf |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | nfbidf.1 | . . 3 | |
2 | nfbidf.2 | . . . 4 | |
3 | 1, 2 | albid 1772 | . . . 4 |
4 | 2, 3 | imbi12d 311 | . . 3 |
5 | 1, 4 | albid 1772 | . 2 |
6 | df-nf 1545 | . 2 | |
7 | df-nf 1545 | . 2 | |
8 | 5, 6, 7 | 3bitr4g 279 | 1 |
Colors of variables: wff setvar class |
Syntax hints: wi 4 wb 176 wal 1540 wnf 1544 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1546 ax-5 1557 ax-17 1616 ax-9 1654 ax-8 1675 ax-11 1746 |
This theorem depends on definitions: df-bi 177 df-ex 1542 df-nf 1545 |
This theorem is referenced by: nfsb4t 2080 dvelimdf 2082 nfcjust 2478 nfceqdf 2489 |
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