Theorem xpeq2d 4809

Description: Equality deduction for cross product. (Contributed by Jeff Madsen, 17-Jun-2010.)

Hypothesis

Ref	Expression
xpeq1d.1	|- (ph -> A = B)

Assertion

Ref	Expression
xpeq2d	|- (ph -> (C X. A) = (C X. B))

Proof of Theorem xpeq2d

Step	Hyp	Ref	Expression
1		xpeq1d.1	. 2 |- (ph -> A = B)
2		xpeq2 4800	. 2 |- (A = B -> (C X. A) = (C X. B))
3	1, 2	syl 15	1 |- (ph -> (C X. A) = (C X. B))

Syntax hints:   -> wi 4   = wceq 1642   X. cxp 4771

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334

This theorem depends on definitions:  df-bi 177  df-an 360  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-opab 4624  df-xp 4785

This theorem is referenced by:  csbresg  4977  fconstg  5252  fconst5  5456  xpsneng  6051  frecxp  6315  frecxpg  6316