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Theorem an42 798
Description: Rearrangement of 4 conjuncts. (Contributed by NM, 7-Feb-1996.)
Assertion
Ref Expression
an42 ⊢ (((φ ∧ ψ) ∧ (χ ∧ θ)) ↔ ((φ ∧ χ) ∧ (θ ∧ ψ)))

Proof of Theorem an42
StepHypRef Expression
1 an4 797 . 2 ⊢ (((φ ∧ ψ) ∧ (χ ∧ θ)) ↔ ((φ ∧ χ) ∧ (ψ ∧ θ)))
2 ancom 437 . . 3 ⊢ ((ψ ∧ θ) ↔ (θ ∧ ψ))
32anbi2i 675 . 2 ⊢ (((φ ∧ χ) ∧ (ψ ∧ θ)) ↔ ((φ ∧ χ) ∧ (θ ∧ ψ)))
41, 3bitri 240 1 ⊢ (((φ ∧ ψ) ∧ (χ ∧ θ)) ↔ ((φ ∧ χ) ∧ (θ ∧ ψ)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 176   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-an 360
This theorem is used by:  rnlem  931  fnpprod  5844
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