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Theorem bi3ant 280
Description: Construct a bi-conditional in antecedent position. (Contributed by Wolf Lammen, 14-May-2013.)
Hypothesis
Ref Expression
bi3ant.1 ⊢ (φ → (ψ → χ))
Assertion
Ref Expression
bi3ant ⊢ (((θ → τ) → φ) → (((τ → θ) → ψ) → ((θ ↔ τ) → χ)))

Proof of Theorem bi3ant
StepHypRef Expression
1 bi1 178 . . 3 ⊢ ((θ ↔ τ) → (θ → τ))
21imim1i 54 . 2 ⊢ (((θ → τ) → φ) → ((θ ↔ τ) → φ))
3 bi2 189 . . 3 ⊢ ((θ ↔ τ) → (τ → θ))
43imim1i 54 . 2 ⊢ (((τ → θ) → ψ) → ((θ ↔ τ) → ψ))
5 bi3ant.1 . . 3 ⊢ (φ → (ψ → χ))
65imim3i 55 . 2 ⊢ (((θ ↔ τ) → φ) → (((θ ↔ τ) → ψ) → ((θ ↔ τ) → χ)))
72, 4, 6syl2im 34 1 ⊢ (((θ → τ) → φ) → (((τ → θ) → ψ) → ((θ ↔ τ) → χ)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 176
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177
This theorem is used by:  bisym  281
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