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Theorem imimorb 847
Description: Simplify an implication between implications. (Contributed by Paul Chapman, 17-Nov-2012.) (Proof shortened by Wolf Lammen, 3-Apr-2013.)
Assertion
Ref Expression
imimorb ⊢ (((ψ → χ) → (φ → χ)) ↔ (φ → (ψ ∨ χ)))

Proof of Theorem imimorb
StepHypRef Expression
1 bi2.04 350 . 2 ⊢ (((ψ → χ) → (φ → χ)) ↔ (φ → ((ψ → χ) → χ)))
2 dfor2 400 . . 3 ⊢ ((ψ ∨ χ) ↔ ((ψ → χ) → χ))
32imbi2i 303 . 2 ⊢ ((φ → (ψ ∨ χ)) ↔ (φ → ((ψ → χ) → χ)))
41, 3bitr4i 243 1 ⊢ (((ψ → χ) → (φ → χ)) ↔ (φ → (ψ ∨ χ)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 176   ∨ wo 357
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-or 359
This theorem is used by: (None)
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