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| Mirrors > Home > NFE Home > Th. List > impbidd | GIF version | ||
| Description: Deduce an equivalence from two implications. (Contributed by Rodolfo Medina, 12-Oct-2010.) |
| Ref | Expression |
|---|---|
| impbidd.1 | ⊢ (φ → (ψ → (χ → θ))) |
| impbidd.2 | ⊢ (φ → (ψ → (θ → χ))) |
| Ref | Expression |
|---|---|
| impbidd | ⊢ (φ → (ψ → (χ ↔ θ))) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | impbidd.1 | . 2 ⊢ (φ → (ψ → (χ → θ))) | |
| 2 | impbidd.2 | . 2 ⊢ (φ → (ψ → (θ → χ))) | |
| 3 | bi3 179 | . 2 ⊢ ((χ → θ) → ((θ → χ) → (χ ↔ θ))) | |
| 4 | 1, 2, 3 | syl6c 60 | 1 ⊢ (φ → (ψ → (χ ↔ θ))) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 176 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 |
| This theorem depends on definitions: df-bi 177 |
| This theorem is referenced by: impbid21d 182 pm5.74 235 |
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