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Mirrors > Home > NFE Home > Th. List > impbidd | GIF version |
Description: Deduce an equivalence from two implications. (Contributed by Rodolfo Medina, 12-Oct-2010.) |
Ref | Expression |
---|---|
impbidd.1 | ⊢ (φ → (ψ → (χ → θ))) |
impbidd.2 | ⊢ (φ → (ψ → (θ → χ))) |
Ref | Expression |
---|---|
impbidd | ⊢ (φ → (ψ → (χ ↔ θ))) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | impbidd.1 | . 2 ⊢ (φ → (ψ → (χ → θ))) | |
2 | impbidd.2 | . 2 ⊢ (φ → (ψ → (θ → χ))) | |
3 | bi3 179 | . 2 ⊢ ((χ → θ) → ((θ → χ) → (χ ↔ θ))) | |
4 | 1, 2, 3 | syl6c 60 | 1 ⊢ (φ → (ψ → (χ ↔ θ))) |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ↔ wb 176 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 |
This theorem depends on definitions: df-bi 177 |
This theorem is referenced by: impbid21d 182 pm5.74 235 |
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