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Theorem oranabs 829
Description: Absorb a disjunct into a conjunct. (Contributed by Roy F. Longton, 23-Jun-2005.) (Proof shortened by Wolf Lammen, 10-Nov-2013.)
Assertion
Ref Expression
oranabs ⊢ (((φ ∨ ¬ ψ) ∧ ψ) ↔ (φ ∧ ψ))

Proof of Theorem oranabs
StepHypRef Expression
1 biortn 395 . . 3 ⊢ (ψ → (φ ↔ (¬ ψ ∨ φ)))
2 orcom 376 . . 3 ⊢ ((¬ ψ ∨ φ) ↔ (φ ∨ ¬ ψ))
31, 2syl6rbb 253 . 2 ⊢ (ψ → ((φ ∨ ¬ ψ) ↔ φ))
43pm5.32ri 619 1 ⊢ (((φ ∨ ¬ ψ) ∧ ψ) ↔ (φ ∧ ψ))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   ↔ wb 176   ∨ wo 357   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-or 359  df-an 360
This theorem is used by: (None)
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