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Theorem pm2.61ddan 767
Description: Elimination of two antecedents. (Contributed by NM, 9-Jul-2013.)
Hypotheses
Ref Expression
pm2.61ddan.1 ⊢ ((φ ∧ ψ) → θ)
pm2.61ddan.2 ⊢ ((φ ∧ χ) → θ)
pm2.61ddan.3 ⊢ ((φ ∧ (¬ ψ ∧ ¬ χ)) → θ)
Assertion
Ref Expression
pm2.61ddan ⊢ (φ → θ)

Proof of Theorem pm2.61ddan
StepHypRef Expression
1 pm2.61ddan.1 . 2 ⊢ ((φ ∧ ψ) → θ)
2 pm2.61ddan.2 . . . 4 ⊢ ((φ ∧ χ) → θ)
32adantlr 695 . . 3 ⊢ (((φ ∧ ¬ ψ) ∧ χ) → θ)
4 pm2.61ddan.3 . . . 4 ⊢ ((φ ∧ (¬ ψ ∧ ¬ χ)) → θ)
54anassrs 629 . . 3 ⊢ (((φ ∧ ¬ ψ) ∧ ¬ χ) → θ)
63, 5pm2.61dan 766 . 2 ⊢ ((φ ∧ ¬ ψ) → θ)
71, 6pm2.61dan 766 1 ⊢ (φ → θ)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-an 360
This theorem is used by: (None)
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