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Mirrors > Home > QLE Home > Th. List > mhlemlem2 | GIF version |
Description: Lemma for Lemma 7.1 of Kalmbach, p. 91. (Contributed by NM, 10-Mar-2002.) |
Ref | Expression |
---|---|
mhlem.1 | (a ∪ b) ≤ (c ∪ d)⊥ |
Ref | Expression |
---|---|
mhlemlem2 | (((a ∪ b) ∪ d) ∩ (b ∪ (c ∪ d))) = (b ∪ d) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | ax-a2 31 | . . . 4 (a ∪ b) = (b ∪ a) | |
2 | 1 | ax-r5 38 | . . 3 ((a ∪ b) ∪ d) = ((b ∪ a) ∪ d) |
3 | ax-a2 31 | . . . 4 (c ∪ d) = (d ∪ c) | |
4 | 3 | lor 70 | . . 3 (b ∪ (c ∪ d)) = (b ∪ (d ∪ c)) |
5 | 2, 4 | 2an 79 | . 2 (((a ∪ b) ∪ d) ∩ (b ∪ (c ∪ d))) = (((b ∪ a) ∪ d) ∩ (b ∪ (d ∪ c))) |
6 | mhlem.1 | . . . 4 (a ∪ b) ≤ (c ∪ d)⊥ | |
7 | ax-a2 31 | . . . 4 (b ∪ a) = (a ∪ b) | |
8 | ax-a2 31 | . . . . 5 (d ∪ c) = (c ∪ d) | |
9 | 8 | ax-r4 37 | . . . 4 (d ∪ c)⊥ = (c ∪ d)⊥ |
10 | 6, 7, 9 | le3tr1 140 | . . 3 (b ∪ a) ≤ (d ∪ c)⊥ |
11 | 10 | mhlemlem1 874 | . 2 (((b ∪ a) ∪ d) ∩ (b ∪ (d ∪ c))) = (b ∪ d) |
12 | 5, 11 | ax-r2 36 | 1 (((a ∪ b) ∪ d) ∩ (b ∪ (c ∪ d))) = (b ∪ d) |
Colors of variables: term |
Syntax hints: = wb 1 ≤ wle 2 ⊥ wn 4 ∪ wo 6 ∩ wa 7 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a4 33 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 ax-r3 439 |
This theorem depends on definitions: df-b 39 df-a 40 df-t 41 df-f 42 df-le1 130 df-le2 131 df-c1 132 df-c2 133 |
This theorem is referenced by: mhlem 876 |
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