Theorem u2lemnab 651

Description: Lemma for Dishkant implication study. (Contributed by NM, 16-Dec-1997.)

Assertion

Ref	Expression
u2lemnab	((a →2 b)⊥ ∩ b) = 0

Proof of Theorem u2lemnab

Step	Hyp	Ref	Expression
1		u2lemonb 636	. . 3 ((a →2 b) ∪ b⊥ ) = 1
2		oran1 91	. . 3 ((a →2 b) ∪ b⊥ ) = ((a →2 b)⊥ ∩ b)⊥
3		df-f 42	. . . . 5 0 = 1⊥
4	3	con2 67	. . . 4 0⊥ = 1
5	4	ax-r1 35	. . 3 1 = 0⊥
6	1, 2, 5	3tr2 64	. 2 ((a →2 b)⊥ ∩ b)⊥ = 0⊥
7	6	con1 66	1 ((a →2 b)⊥ ∩ b) = 0

Syntax hints:   = wb 1  ^⊥ wn 4   ∪ wo 6   ∩ wa 7  1wt 8  0wf 9   →₂ wi2 13

This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a4 33  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38

This theorem depends on definitions:  df-a 40  df-t 41  df-f 42  df-i2 45

This theorem is referenced by: (None)