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Mirrors > Home > QLE Home > Th. List > u3lem12 | GIF version |
Description: Lemma for unified implication study. (Contributed by NM, 18-Jan-1998.) |
Ref | Expression |
---|---|
u3lem12 | (a →3 (a →3 b⊥ ))⊥ = (a ∩ b) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | lem4 511 | . . 3 (a →3 (a →3 b⊥ )) = (a⊥ ∪ b⊥ ) | |
2 | 1 | ax-r4 37 | . 2 (a →3 (a →3 b⊥ ))⊥ = (a⊥ ∪ b⊥ )⊥ |
3 | df-a 40 | . . 3 (a ∩ b) = (a⊥ ∪ b⊥ )⊥ | |
4 | 3 | ax-r1 35 | . 2 (a⊥ ∪ b⊥ )⊥ = (a ∩ b) |
5 | 2, 4 | ax-r2 36 | 1 (a →3 (a →3 b⊥ ))⊥ = (a ∩ b) |
Colors of variables: term |
Syntax hints: = wb 1 ⊥ wn 4 ∪ wo 6 ∩ wa 7 →3 wi3 14 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a4 33 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 ax-r3 439 |
This theorem depends on definitions: df-b 39 df-a 40 df-t 41 df-f 42 df-i3 46 df-le1 130 df-le2 131 df-c1 132 df-c2 133 |
This theorem is referenced by: (None) |
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