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Mirrors > Home > QLE Home > Th. List > vneulem8 | GIF version |
Description: Part of von Neumann's lemma. Lemma 9, Kalmbach p. 96. (Contributed by NM, 31-Mar-2011.) |
Ref | Expression |
---|---|
vneulem6.1 | ((a ∪ b) ∩ (c ∪ d)) = 0 |
Ref | Expression |
---|---|
vneulem8 | (((a ∪ b) ∪ d) ∩ ((b ∪ c) ∪ d)) = (b ∪ d) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | vneulem6.1 | . . 3 ((a ∪ b) ∩ (c ∪ d)) = 0 | |
2 | 1 | vneulem6 1136 | . 2 (((a ∪ b) ∪ d) ∩ ((b ∪ c) ∪ d)) = ((c ∩ a) ∪ (b ∪ d)) |
3 | 1 | vneulem7 1137 | . 2 ((c ∩ a) ∪ (b ∪ d)) = (b ∪ d) |
4 | 2, 3 | tr 62 | 1 (((a ∪ b) ∪ d) ∩ ((b ∪ c) ∪ d)) = (b ∪ d) |
Colors of variables: term |
Syntax hints: = wb 1 ∪ wo 6 ∩ wa 7 0wf 9 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 ax-ml 1122 |
This theorem depends on definitions: df-a 40 df-t 41 df-f 42 df-le1 130 df-le2 131 |
This theorem is referenced by: vneulem10 1140 vneulem15 1145 |
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