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Theorem s8eqd 13413
Description: Equality theorem for a length 8 word. (Contributed by Mario Carneiro, 27-Feb-2016.)
Hypotheses
Ref Expression
s2eqd.1 (𝜑𝐴 = 𝑁)
s2eqd.2 (𝜑𝐵 = 𝑂)
s3eqd.3 (𝜑𝐶 = 𝑃)
s4eqd.4 (𝜑𝐷 = 𝑄)
s5eqd.5 (𝜑𝐸 = 𝑅)
s6eqd.6 (𝜑𝐹 = 𝑆)
s7eqd.6 (𝜑𝐺 = 𝑇)
s8eqd.6 (𝜑𝐻 = 𝑈)
Assertion
Ref Expression
s8eqd (𝜑 → ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺𝐻”⟩ = ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇𝑈”⟩)

Proof of Theorem s8eqd
StepHypRef Expression
1 s2eqd.1 . . . 4 (𝜑𝐴 = 𝑁)
2 s2eqd.2 . . . 4 (𝜑𝐵 = 𝑂)
3 s3eqd.3 . . . 4 (𝜑𝐶 = 𝑃)
4 s4eqd.4 . . . 4 (𝜑𝐷 = 𝑄)
5 s5eqd.5 . . . 4 (𝜑𝐸 = 𝑅)
6 s6eqd.6 . . . 4 (𝜑𝐹 = 𝑆)
7 s7eqd.6 . . . 4 (𝜑𝐺 = 𝑇)
81, 2, 3, 4, 5, 6, 7s7eqd 13412 . . 3 (𝜑 → ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺”⟩ = ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇”⟩)
9 s8eqd.6 . . . 4 (𝜑𝐻 = 𝑈)
109s1eqd 13182 . . 3 (𝜑 → ⟨“𝐻”⟩ = ⟨“𝑈”⟩)
118, 10oveq12d 6544 . 2 (𝜑 → (⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺”⟩ ++ ⟨“𝐻”⟩) = (⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇”⟩ ++ ⟨“𝑈”⟩))
12 df-s8 13398 . 2 ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺𝐻”⟩ = (⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺”⟩ ++ ⟨“𝐻”⟩)
13 df-s8 13398 . 2 ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇𝑈”⟩ = (⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇”⟩ ++ ⟨“𝑈”⟩)
1411, 12, 133eqtr4g 2668 1 (𝜑 → ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺𝐻”⟩ = ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇𝑈”⟩)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1474  (class class class)co 6526   ++ cconcat 13096  ⟨“cs1 13097  ⟨“cs7 13390  ⟨“cs8 13391
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1712  ax-4 1727  ax-5 1826  ax-6 1874  ax-7 1921  ax-10 2005  ax-11 2020  ax-12 2033  ax-13 2233  ax-ext 2589
This theorem depends on definitions:  df-bi 195  df-or 383  df-an 384  df-3an 1032  df-tru 1477  df-ex 1695  df-nf 1700  df-sb 1867  df-clab 2596  df-cleq 2602  df-clel 2605  df-nfc 2739  df-rex 2901  df-rab 2904  df-v 3174  df-dif 3542  df-un 3544  df-in 3546  df-ss 3553  df-nul 3874  df-if 4036  df-sn 4125  df-pr 4127  df-op 4131  df-uni 4367  df-br 4578  df-iota 5753  df-fv 5797  df-ov 6529  df-s1 13105  df-s2 13392  df-s3 13393  df-s4 13394  df-s5 13395  df-s6 13396  df-s7 13397  df-s8 13398
This theorem is referenced by: (None)
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