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Mirrors > Home > ILE Home > Th. List > cdeqth | Unicode version |
Description: Deduce conditional equality from a theorem. (Contributed by Mario Carneiro, 11-Aug-2016.) |
Ref | Expression |
---|---|
cdeqth.1 |
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Ref | Expression |
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cdeqth |
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Step | Hyp | Ref | Expression |
---|---|---|---|
1 | cdeqth.1 |
. . 3
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2 | 1 | a1i 9 |
. 2
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3 | 2 | cdeqi 2898 |
1
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Colors of variables: wff set class |
Syntax hints: CondEqwcdeq 2896 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 |
This theorem depends on definitions: df-bi 116 df-cdeq 2897 |
This theorem is referenced by: cdeqal1 2904 cdeqab1 2905 nfccdeq 2911 |
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