Theorem cdeqi 2983

Description: Deduce conditional equality. (Contributed by Mario Carneiro, 11-Aug-2016.)

Hypothesis

Ref	Expression
cdeqi.1	|- ( x = y -> ph )

Assertion

Ref	Expression
cdeqi	|- CondEq ( x = y -> ph )

Proof of Theorem cdeqi

Step	Hyp	Ref	Expression
1		cdeqi.1	. 2 |- ( x = y -> ph )
2		df-cdeq 2982	. 2 |- (CondEq ( x = y -> ph ) <-> ( x = y -> ph ) )
3	1, 2	mpbir 146	1 |- CondEq ( x = y -> ph )

Syntax hints:   -> wi 4  CondEqwcdeq 2981

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This theorem depends on definitions:  df-bi 117  df-cdeq 2982

This theorem is referenced by:  cdeqth  2985  cdeqnot  2986  cdeqal  2987  cdeqab  2988  cdeqim  2991  cdeqcv  2992  cdeqeq  2993  cdeqel  2994