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| Mirrors > Home > ILE Home > Th. List > elnelall | GIF version | ||
| Description: A contradiction concerning membership implies anything. (Contributed by Alexander van der Vekens, 25-Jan-2018.) |
| Ref | Expression |
|---|---|
| elnelall | ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∉ 𝐵 → 𝜑)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | df-nel 2463 | . 2 ⊢ (𝐴 ∉ 𝐵 ↔ ¬ 𝐴 ∈ 𝐵) | |
| 2 | pm2.24 622 | . 2 ⊢ (𝐴 ∈ 𝐵 → (¬ 𝐴 ∈ 𝐵 → 𝜑)) | |
| 3 | 1, 2 | biimtrid 152 | 1 ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∉ 𝐵 → 𝜑)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∈ wcel 2167 ∉ wnel 2462 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-in2 616 |
| This theorem depends on definitions: df-bi 117 df-nel 2463 |
| This theorem is referenced by: xnn0lenn0nn0 9957 |
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