Theorem rspa 2525

Description: Restricted specialization. (Contributed by Glauco Siliprandi, 11-Dec-2019.)

Assertion

Ref	Expression
rspa	⊢ ((∀𝑥 ∈ 𝐴 𝜑 ∧ 𝑥 ∈ 𝐴) → 𝜑)

Proof of Theorem rspa

Step	Hyp	Ref	Expression
1		rsp 2524	. 2 ⊢ (∀𝑥 ∈ 𝐴 𝜑 → (𝑥 ∈ 𝐴 → 𝜑))
2	1	imp 124	1 ⊢ ((∀𝑥 ∈ 𝐴 𝜑 ∧ 𝑥 ∈ 𝐴) → 𝜑)

Syntax hints:   → wi 4   ∧ wa 104   ∈ wcel 2148  ∀wral 2455

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-4 1510

This theorem depends on definitions:  df-bi 117  df-ral 2460

This theorem is referenced by: (None)