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Theorem 3an4ancom24 48283
Description: Commutative law for a conjunction with a triple conjunction: second and forth positions interchanged. (Contributed by AV, 18-Feb-2022.)
Assertion
Ref Expression
3an4ancom24 (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) ↔ ((𝜑 ∧ 𝜃 ∧ 𝜒) ∧ 𝜓))

Proof of Theorem 3an4ancom24
StepHypRef Expression
1 an4com24 48282 . 2 (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜑 ∧ 𝜃) ∧ (𝜒 ∧ 𝜓)))
2 3an4anass 1122 . 2 (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)))
3 3an4anass 1122 . 2 (((𝜑 ∧ 𝜃 ∧ 𝜒) ∧ 𝜓) ↔ ((𝜑 ∧ 𝜃) ∧ (𝜒 ∧ 𝜓)))
41, 2, 33bitr4i 306 1 (((𝜑 ∧ 𝜓 ∧ 𝜒) ∧ 𝜃) ↔ ((𝜑 ∧ 𝜃 ∧ 𝜒) ∧ 𝜓))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401   ∧ w3a 1103
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105
This theorem is used by: (None)
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