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Theorem 4an21 48340
Description: Rearrangement of 4 conjuncts with a triple conjunction. (Contributed by AV, 4-Mar-2022.)
Assertion
Ref Expression
4an21 (((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒 ∧ 𝜃)))

Proof of Theorem 4an21
StepHypRef Expression
1 3anass 1111 . 2 (((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃) ↔ ((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)))
2 ancom 466 . . . 4 ((𝜑 ∧ 𝜓) ↔ (𝜓 ∧ 𝜑))
32anbi1i 636 . . 3 (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ ((𝜓 ∧ 𝜑) ∧ (𝜒 ∧ 𝜃)))
4 anass 474 . . . 4 (((𝜓 ∧ 𝜑) ∧ (𝜒 ∧ 𝜃)) ↔ (𝜓 ∧ (𝜑 ∧ (𝜒 ∧ 𝜃))))
5 3anass 1111 . . . . . 6 ((𝜑 ∧ 𝜒 ∧ 𝜃) ↔ (𝜑 ∧ (𝜒 ∧ 𝜃)))
65bicomi 227 . . . . 5 ((𝜑 ∧ (𝜒 ∧ 𝜃)) ↔ (𝜑 ∧ 𝜒 ∧ 𝜃))
76anbi2i 635 . . . 4 ((𝜓 ∧ (𝜑 ∧ (𝜒 ∧ 𝜃))) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒 ∧ 𝜃)))
84, 7bitri 278 . . 3 (((𝜓 ∧ 𝜑) ∧ (𝜒 ∧ 𝜃)) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒 ∧ 𝜃)))
93, 8bitri 278 . 2 (((𝜑 ∧ 𝜓) ∧ (𝜒 ∧ 𝜃)) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒 ∧ 𝜃)))
101, 9bitri 278 1 (((𝜑 ∧ 𝜓) ∧ 𝜒 ∧ 𝜃) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒 ∧ 𝜃)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401   ∧ w3a 1103
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105
This theorem is used by: (None)
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