Theorem alfal 1811

Description: For all sets, ¬ ⊥ is true. (Contributed by Anthony Hart, 13-Sep-2011.)

Assertion

Ref	Expression
alfal	⊢ ∀𝑥 ¬ ⊥

Proof of Theorem alfal

Step	Hyp	Ref	Expression
1		fal 1553	. 2 ⊢ ¬ ⊥
2	1	ax-gen 1798	1 ⊢ ∀𝑥 ¬ ⊥

Syntax hints:  ¬ wn 3  ∀wal 1537  ⊥wfal 1551

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1798

This theorem depends on definitions:  df-bi 206  df-tru 1542  df-fal 1552

This theorem is referenced by:  nalfal  34592