Theorem bi13impib 41995

Description: 3impib 1114 with the outer implication of the hypothesis a biconditional. (Contributed by Alan Sare, 6-Nov-2017.)

Hypothesis

Ref	Expression
bi13impib.1	⊢ (𝜑 ↔ ((𝜓 ∧ 𝜒) → 𝜃))

Assertion

Ref	Expression
bi13impib	⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃)

Proof of Theorem bi13impib

Step	Hyp	Ref	Expression
1		bi13impib.1	. . 3 ⊢ (𝜑 ↔ ((𝜓 ∧ 𝜒) → 𝜃))
2	1	biimpi 215	. 2 ⊢ (𝜑 → ((𝜓 ∧ 𝜒) → 𝜃))
3	2	3impib 1114	1 ⊢ ((𝜑 ∧ 𝜓 ∧ 𝜒) → 𝜃)

Syntax hints:   → wi 4   ↔ wb 205   ∧ wa 395   ∧ w3a 1085

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 206  df-an 396  df-3an 1087

This theorem is referenced by: (None)