Theorem nanbi2d 1507

Description: Introduce a left anti-conjunct to both sides of a logical equivalence. (Contributed by SF, 2-Jan-2018.)

Hypothesis

Ref	Expression
nanbid.1	⊢ (𝜑 → (𝜓 ↔ 𝜒))

Assertion

Ref	Expression
nanbi2d	⊢ (𝜑 → ((𝜃 ⊼ 𝜓) ↔ (𝜃 ⊼ 𝜒)))

Proof of Theorem nanbi2d

Step	Hyp	Ref	Expression
1		nanbid.1	. 2 ⊢ (𝜑 → (𝜓 ↔ 𝜒))
2		nanbi2 1501	. 2 ⊢ ((𝜓 ↔ 𝜒) → ((𝜃 ⊼ 𝜓) ↔ (𝜃 ⊼ 𝜒)))
3	1, 2	syl 17	1 ⊢ (𝜑 → ((𝜃 ⊼ 𝜓) ↔ (𝜃 ⊼ 𝜒)))

Syntax hints:   → wi 4   ↔ wb 206   ⊼ wnan 1490

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-an 396  df-nan 1491

This theorem is referenced by: (None)