Theorem nfra1 2664

Description: x is not free in A.x e. Aph. (Contributed by NM, 18-Oct-1996.) (Revised by Mario Carneiro, 7-Oct-2016.)

Assertion

Ref	Expression
nfra1	|- F/xA.x e. A ph

Proof of Theorem nfra1

Step	Hyp	Ref	Expression
1		df-ral 2619	. 2 |- (A.x e. A ph <-> A.x(x e. A -> ph))
2		nfa1 1788	. 2 |- F/xA.x(x e. A -> ph)
3	1, 2	nfxfr 1570	1 |- F/xA.x e. A ph

Syntax hints:   -> wi 4  A.wal 1540   F/wnf 1544   e. wcel 1710  A.wral 2614

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-11 1746

This theorem depends on definitions:  df-bi 177  df-ex 1542  df-nf 1545  df-ral 2619

This theorem is referenced by:  nfra2  2668  r19.12  2727  ralbi  2750  ralcom2  2775  nfss  3266  ralidm  3653  nfii1  3998  dfiun2g  3999  ncfinraise  4481  fun11iun  5305  chfnrn  5399  ffnfv  5427  mpteq12f  5655  mpt2eq123  5661  fvmptss  5705