Theorem sselda 3274

Description: Membership deduction from subclass relationship. (Contributed by NM, 26-Jun-2014.)

Hypothesis

Ref	Expression
sseld.1	|- (ph -> A C_ B)

Assertion

Ref	Expression
sselda	|- ((ph /\ C e. A) -> C e. B)

Proof of Theorem sselda

Step	Hyp	Ref	Expression
1		sseld.1	. . 3 |- (ph -> A C_ B)
2	1	sseld 3273	. 2 |- (ph -> (C e. A -> C e. B))
3	2	imp 418	1 |- ((ph /\ C e. A) -> C e. B)

Syntax hints:   -> wi 4   /\ wa 358   e. wcel 1710   C_ wss 3258

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-v 2862  df-nin 3212  df-compl 3213  df-in 3214  df-ss 3260

This theorem is referenced by:  vfinncvntsp  4550  vfinspsslem1  4551  vfinspclt  4553  ffvresb  5432  spaccl  6287  spacis  6289  nchoicelem4  6293