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Theorem an31 775
Description: A rearrangement of conjuncts. (Contributed by NM, 24-Jun-2012.) (Proof shortened by Wolf Lammen, 31-Dec-2012.)
Assertion
Ref Expression
an31 ⊢ (((φ ∧ ψ) ∧ χ) ↔ ((χ ∧ ψ) ∧ φ))

Proof of Theorem an31
StepHypRef Expression
1 an13 774 . 2 ⊢ ((φ ∧ (ψ ∧ χ)) ↔ (χ ∧ (ψ ∧ φ)))
2 anass 630 . 2 ⊢ (((φ ∧ ψ) ∧ χ) ↔ (φ ∧ (ψ ∧ χ)))
3 anass 630 . 2 ⊢ (((χ ∧ ψ) ∧ φ) ↔ (χ ∧ (ψ ∧ φ)))
41, 2, 33bitr4i 268 1 ⊢ (((φ ∧ ψ) ∧ χ) ↔ ((χ ∧ ψ) ∧ φ))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 176   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-an 360
This theorem is used by:  euind  3024  reuind  3040
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