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Theorem an13 774
Description: A rearrangement of conjuncts. (Contributed by NM, 24-Jun-2012.) (Proof shortened by Wolf Lammen, 31-Dec-2012.)
Assertion
Ref Expression
an13 ⊢ ((φ ∧ (ψ ∧ χ)) ↔ (χ ∧ (ψ ∧ φ)))

Proof of Theorem an13
StepHypRef Expression
1 an12 772 . 2 ⊢ ((φ ∧ (ψ ∧ χ)) ↔ (ψ ∧ (φ ∧ χ)))
2 anass 630 . 2 ⊢ (((ψ ∧ φ) ∧ χ) ↔ (ψ ∧ (φ ∧ χ)))
3 ancom 437 . 2 ⊢ (((ψ ∧ φ) ∧ χ) ↔ (χ ∧ (ψ ∧ φ)))
41, 2, 33bitr2i 264 1 ⊢ ((φ ∧ (ψ ∧ χ)) ↔ (χ ∧ (ψ ∧ φ)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 176   ∧ wa 358
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-an 360
This theorem is used by:  an31  775  eqvinop  4607  elxp2  4803  iunfopab  5205
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