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Mirrors > Home > QLE Home > Th. List > lem4.6.6i0j2 | GIF version |
Description: Equation 4.14 of [MegPav2000] p. 23. The variable i in the paper is set to 0, and j is set to 2. (Contributed by Roy F. Longton, 1-Jul-2005.) |
Ref | Expression |
---|---|
lem4.6.6i0j2 | ((a →0 b) ∪ (a →2 b)) = (a →0 b) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | leid 148 | . . . 4 (a⊥ ∪ b) ≤ (a⊥ ∪ b) | |
2 | leor 159 | . . . . 5 b ≤ (a⊥ ∪ b) | |
3 | leao1 162 | . . . . 5 (a⊥ ∩ b⊥ ) ≤ (a⊥ ∪ b) | |
4 | 2, 3 | lel2or 170 | . . . 4 (b ∪ (a⊥ ∩ b⊥ )) ≤ (a⊥ ∪ b) |
5 | 1, 4 | lel2or 170 | . . 3 ((a⊥ ∪ b) ∪ (b ∪ (a⊥ ∩ b⊥ ))) ≤ (a⊥ ∪ b) |
6 | leo 158 | . . 3 (a⊥ ∪ b) ≤ ((a⊥ ∪ b) ∪ (b ∪ (a⊥ ∩ b⊥ ))) | |
7 | 5, 6 | lebi 145 | . 2 ((a⊥ ∪ b) ∪ (b ∪ (a⊥ ∩ b⊥ ))) = (a⊥ ∪ b) |
8 | df-i0 43 | . . 3 (a →0 b) = (a⊥ ∪ b) | |
9 | df-i2 45 | . . 3 (a →2 b) = (b ∪ (a⊥ ∩ b⊥ )) | |
10 | 8, 9 | 2or 72 | . 2 ((a →0 b) ∪ (a →2 b)) = ((a⊥ ∪ b) ∪ (b ∪ (a⊥ ∩ b⊥ ))) |
11 | 7, 10, 8 | 3tr1 63 | 1 ((a →0 b) ∪ (a →2 b)) = (a →0 b) |
Colors of variables: term |
Syntax hints: = wb 1 ⊥ wn 4 ∪ wo 6 ∩ wa 7 →0 wi0 11 →2 wi2 13 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 |
This theorem depends on definitions: df-a 40 df-t 41 df-f 42 df-i0 43 df-i2 45 df-le1 130 df-le2 131 |
This theorem is referenced by: (None) |
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