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Mirrors > Home > QLE Home > Th. List > negantlem7 | GIF version |
Description: Negated antecedent identity. (Contributed by NM, 6-Aug-2001.) |
Ref | Expression |
---|---|
negant.1 | (a →1 c) = (b →1 c) |
Ref | Expression |
---|---|
negantlem7 | (a ∪ c) = (b ∪ c) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | negant.1 | . . . 4 (a →1 c) = (b →1 c) | |
2 | 1 | negantlem5 853 | . . 3 (a⊥ ∩ c⊥ ) = (b⊥ ∩ c⊥ ) |
3 | anor3 90 | . . 3 (a⊥ ∩ c⊥ ) = (a ∪ c)⊥ | |
4 | anor3 90 | . . 3 (b⊥ ∩ c⊥ ) = (b ∪ c)⊥ | |
5 | 2, 3, 4 | 3tr2 64 | . 2 (a ∪ c)⊥ = (b ∪ c)⊥ |
6 | 5 | con1 66 | 1 (a ∪ c) = (b ∪ c) |
Colors of variables: term |
Syntax hints: = wb 1 ⊥ wn 4 ∪ wo 6 ∩ wa 7 →1 wi1 12 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a4 33 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 ax-r3 439 |
This theorem depends on definitions: df-b 39 df-a 40 df-t 41 df-f 42 df-i1 44 df-le1 130 df-le2 131 df-c1 132 df-c2 133 |
This theorem is referenced by: negant0 857 |
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