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Mirrors > Home > QLE Home > Th. List > oa3to4lem5 | GIF version |
Description: Lemma for orthoarguesian law (Godowski/Greechie 3-variable to 4-variable proof). (Contributed by NM, 19-Dec-1998.) |
Ref | Expression |
---|---|
oa3to4lem5.1 | ((a ∪ b) ∩ (c ∪ d)) ≤ (a ∪ (b ∩ (d ∪ ((a ∪ c) ∩ (b ∪ d))))) |
Ref | Expression |
---|---|
oa3to4lem5 | ((b ∪ a) ∩ (d ∪ c)) ≤ (a ∪ (b ∩ (d ∪ ((b ∪ d) ∩ (a ∪ c))))) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | oa3to4lem5.1 | . 2 ((a ∪ b) ∩ (c ∪ d)) ≤ (a ∪ (b ∩ (d ∪ ((a ∪ c) ∩ (b ∪ d))))) | |
2 | ax-a2 31 | . . 3 (b ∪ a) = (a ∪ b) | |
3 | ax-a2 31 | . . 3 (d ∪ c) = (c ∪ d) | |
4 | 2, 3 | 2an 79 | . 2 ((b ∪ a) ∩ (d ∪ c)) = ((a ∪ b) ∩ (c ∪ d)) |
5 | ancom 74 | . . . . 5 ((b ∪ d) ∩ (a ∪ c)) = ((a ∪ c) ∩ (b ∪ d)) | |
6 | 5 | lor 70 | . . . 4 (d ∪ ((b ∪ d) ∩ (a ∪ c))) = (d ∪ ((a ∪ c) ∩ (b ∪ d))) |
7 | 6 | lan 77 | . . 3 (b ∩ (d ∪ ((b ∪ d) ∩ (a ∪ c)))) = (b ∩ (d ∪ ((a ∪ c) ∩ (b ∪ d)))) |
8 | 7 | lor 70 | . 2 (a ∪ (b ∩ (d ∪ ((b ∪ d) ∩ (a ∪ c))))) = (a ∪ (b ∩ (d ∪ ((a ∪ c) ∩ (b ∪ d))))) |
9 | 1, 4, 8 | le3tr1 140 | 1 ((b ∪ a) ∩ (d ∪ c)) ≤ (a ∪ (b ∩ (d ∪ ((b ∪ d) ∩ (a ∪ c))))) |
Colors of variables: term |
Syntax hints: ≤ wle 2 ∪ wo 6 ∩ wa 7 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 |
This theorem depends on definitions: df-a 40 df-le1 130 df-le2 131 |
This theorem is referenced by: oa3to4 951 |
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