Theorem oa6 1036

Description: Derivation of 6-variable orthoarguesian law from 4-variable version. (Contributed by NM, 18-Dec-1998.)

Hypotheses

Ref	Expression
oa6.1	a ≤ b⊥
oa6.2	c ≤ d⊥
oa6.3	e ≤ f⊥

Assertion

Ref	Expression
oa6	(((a ∪ b) ∩ (c ∪ d)) ∩ (e ∪ f)) ≤ (b ∪ (a ∩ (c ∪ (((a ∪ c) ∩ (b ∪ d)) ∩ (((a ∪ e) ∩ (b ∪ f)) ∪ ((c ∪ e) ∩ (d ∪ f)))))))

Proof of Theorem oa6

Step	Hyp	Ref	Expression
1		oa6.1	. 2 a ≤ b⊥
2		oa6.2	. 2 c ≤ d⊥
3		oa6.3	. 2 e ≤ f⊥
4		id 59	. 2 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ )) = (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))
5		id 59	. 2 a⊥ = a⊥
6		id 59	. 2 c⊥ = c⊥
7		id 59	. 2 e⊥ = e⊥
8		axoa4b 1035	. 2 ((a⊥ →1 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))) ∩ (a⊥ ∪ (c⊥ ∩ (((a⊥ ∩ c⊥ ) ∪ ((a⊥ →1 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))) ∩ (c⊥ →1 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))))) ∪ (((a⊥ ∩ e⊥ ) ∪ ((a⊥ →1 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))) ∩ (e⊥ →1 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))))) ∩ ((c⊥ ∩ e⊥ ) ∪ ((c⊥ →1 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))) ∩ (e⊥ →1 (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ )))))))))) ≤ (((a⊥ ∩ b⊥ ) ∪ (c⊥ ∩ d⊥ )) ∪ (e⊥ ∩ f⊥ ))
9	1, 2, 3, 4, 5, 6, 7, 8	oa4to6 965	1 (((a ∪ b) ∩ (c ∪ d)) ∩ (e ∪ f)) ≤ (b ∪ (a ∩ (c ∪ (((a ∪ c) ∩ (b ∪ d)) ∩ (((a ∪ e) ∩ (b ∪ f)) ∪ ((c ∪ e) ∩ (d ∪ f)))))))

Syntax hints:   ≤ wle 2  ^⊥ wn 4   ∪ wo 6   ∩ wa 7

This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a4 33  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38  ax-r3 439  ax-4oa 1033

This theorem depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42  df-i1 44  df-le1 130  df-le2 131  df-c1 132  df-c2 133

This theorem is referenced by:  axoa4a  1037