Theorem brprop 30433

Description: Binary relation for a pair of ordered pairs. (Contributed by Thierry Arnoux, 24-Sep-2023.)

Hypotheses

Ref	Expression
brprop.a	⊢ (𝜑 → 𝐴 ∈ 𝑉)
brprop.b	⊢ (𝜑 → 𝐵 ∈ 𝑊)
brprop.c	⊢ (𝜑 → 𝐶 ∈ 𝑉)
brprop.d	⊢ (𝜑 → 𝐷 ∈ 𝑊)

Assertion

Ref	Expression
brprop	⊢ (𝜑 → (𝑋{⟨𝐴, 𝐵⟩, ⟨𝐶, 𝐷⟩}𝑌 ↔ ((𝑋 = 𝐴 ∧ 𝑌 = 𝐵) ∨ (𝑋 = 𝐶 ∧ 𝑌 = 𝐷))))

Proof of Theorem brprop

Step	Hyp	Ref	Expression
1		df-pr 4570	. . . 4 ⊢ {⟨𝐴, 𝐵⟩, ⟨𝐶, 𝐷⟩} = ({⟨𝐴, 𝐵⟩} ∪ {⟨𝐶, 𝐷⟩})
2	1	breqi 5072	. . 3 ⊢ (𝑋{⟨𝐴, 𝐵⟩, ⟨𝐶, 𝐷⟩}𝑌 ↔ 𝑋({⟨𝐴, 𝐵⟩} ∪ {⟨𝐶, 𝐷⟩})𝑌)
3		brun 5117	. . 3 ⊢ (𝑋({⟨𝐴, 𝐵⟩} ∪ {⟨𝐶, 𝐷⟩})𝑌 ↔ (𝑋{⟨𝐴, 𝐵⟩}𝑌 ∨ 𝑋{⟨𝐶, 𝐷⟩}𝑌))
4	2, 3	bitri 277	. 2 ⊢ (𝑋{⟨𝐴, 𝐵⟩, ⟨𝐶, 𝐷⟩}𝑌 ↔ (𝑋{⟨𝐴, 𝐵⟩}𝑌 ∨ 𝑋{⟨𝐶, 𝐷⟩}𝑌))
5		brprop.a	. . . 4 ⊢ (𝜑 → 𝐴 ∈ 𝑉)
6		brprop.b	. . . 4 ⊢ (𝜑 → 𝐵 ∈ 𝑊)
7		brsnop 30429	. . . 4 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (𝑋{⟨𝐴, 𝐵⟩}𝑌 ↔ (𝑋 = 𝐴 ∧ 𝑌 = 𝐵)))
8	5, 6, 7	syl2anc 586	. . 3 ⊢ (𝜑 → (𝑋{⟨𝐴, 𝐵⟩}𝑌 ↔ (𝑋 = 𝐴 ∧ 𝑌 = 𝐵)))
9		brprop.c	. . . 4 ⊢ (𝜑 → 𝐶 ∈ 𝑉)
10		brprop.d	. . . 4 ⊢ (𝜑 → 𝐷 ∈ 𝑊)
11		brsnop 30429	. . . 4 ⊢ ((𝐶 ∈ 𝑉 ∧ 𝐷 ∈ 𝑊) → (𝑋{⟨𝐶, 𝐷⟩}𝑌 ↔ (𝑋 = 𝐶 ∧ 𝑌 = 𝐷)))
12	9, 10, 11	syl2anc 586	. . 3 ⊢ (𝜑 → (𝑋{⟨𝐶, 𝐷⟩}𝑌 ↔ (𝑋 = 𝐶 ∧ 𝑌 = 𝐷)))
13	8, 12	orbi12d 915	. 2 ⊢ (𝜑 → ((𝑋{⟨𝐴, 𝐵⟩}𝑌 ∨ 𝑋{⟨𝐶, 𝐷⟩}𝑌) ↔ ((𝑋 = 𝐴 ∧ 𝑌 = 𝐵) ∨ (𝑋 = 𝐶 ∧ 𝑌 = 𝐷))))
14	4, 13	syl5bb 285	1 ⊢ (𝜑 → (𝑋{⟨𝐴, 𝐵⟩, ⟨𝐶, 𝐷⟩}𝑌 ↔ ((𝑋 = 𝐴 ∧ 𝑌 = 𝐵) ∨ (𝑋 = 𝐶 ∧ 𝑌 = 𝐷))))

Syntax hints:   → wi 4   ↔ wb 208   ∧ wa 398   ∨ wo 843   = wceq 1537   ∈ wcel 2114   ∪ cun 3934  {csn 4567  {cpr 4569  ⟨cop 4573   class class class wbr 5066

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2116  ax-9 2124  ax-10 2145  ax-11 2161  ax-12 2177  ax-ext 2793  ax-sep 5203  ax-nul 5210  ax-pr 5330

This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-3an 1085  df-tru 1540  df-ex 1781  df-nf 1785  df-sb 2070  df-clab 2800  df-cleq 2814  df-clel 2893  df-nfc 2963  df-rab 3147  df-v 3496  df-dif 3939  df-un 3941  df-in 3943  df-ss 3952  df-nul 4292  df-if 4468  df-sn 4568  df-pr 4570  df-op 4574  df-br 5067

This theorem is referenced by: (None)