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Related theorems GIF version |
| Description: At least two sets exist
(or in terms of first-order logic, the universe
of discourse has two or more objects). Note that we may not substitute
the same variable for both x and
y (as indicated by the distinct
variable requirement), for otherwise we would contradict stdpc6 1125.
Assuming that ZF set theory is consistent, we cannot prove this theorem
unless we specify that x and
y be distinct. Specifically,
theorem cla4ev 1865 requires that x must not occur in the subexpression
¬ y = {∅} in step 4 nor in
the subexpression ¬ y = ∅ in
step 9. The proof verifier will require that x and y be in a
distinct variable group to ensure this. You can check this by deleting
the $d statement in set.mm and rerunning the verifier, which will print
a detailed explanation of the distinct variable violation.
See dtruALT 2744 for a version proved without using ax-16 1208, ax-ext 1457, or ax-sep 2699. |
| Ref | Expression |
|---|---|
| dtru | ⊢ ¬ ∀x x = y |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 0inp0 2734 | . . . 4 ⊢ (y = ∅ → ¬ y = {∅}) | |
| 2 | p0ex 2766 | . . . . 5 ⊢ {∅} ∈ V | |
| 3 | eqeq2 1481 | . . . . . 6 ⊢ (x = {∅} → (y = x ↔ y = {∅})) | |
| 4 | 3 | negbid 610 | . . . . 5 ⊢ (x = {∅} → (¬ y = x ↔ ¬ y = {∅})) |
| 5 | 2, 4 | cla4ev 1865 | . . . 4 ⊢ (¬ y = {∅} → ∃x ¬ y = x) |
| 6 | 1, 5 | syl 10 | . . 3 ⊢ (y = ∅ → ∃x ¬ y = x) |
| 7 | 0ex 2707 | . . . 4 ⊢ ∅ ∈ V | |
| 8 | eqeq2 1481 | . . . . 5 ⊢ (x = ∅ → (y = x ↔ y = ∅)) | |
| 9 | 8 | negbid 610 | . . . 4 ⊢ (x = ∅ → (¬ y = x ↔ ¬ y = ∅)) |
| 10 | 7, 9 | cla4ev 1865 | . . 3 ⊢ (¬ y = ∅ → ∃x ¬ y = x) |
| 11 | 6, 10 | pm2.61i 126 | . 2 ⊢ ∃x ¬ y = x |
| 12 | exnal 1036 | . . 3 ⊢ (∃x ¬ y = x ↔ ¬ ∀x y = x) | |
| 13 | eqcom 1474 | . . . . 5 ⊢ (y = x ↔ x = y) | |
| 14 | 13 | albii 997 | . . . 4 ⊢ (∀x y = x ↔ ∀x x = y) |
| 15 | 14 | negbii 187 | . . 3 ⊢ (¬ ∀x y = x ↔ ¬ ∀x x = y) |
| 16 | 12, 15 | bitr 173 | . 2 ⊢ (∃x ¬ y = x ↔ ¬ ∀x x = y) |
| 17 | 11, 16 | mpbi 189 | 1 ⊢ ¬ ∀x x = y |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 2 ∀wal 952 = wceq 954 ∃wex 978 ∅c0 2276 {csn 2405 |
| This theorem is referenced by: dtrucor 2769 dvdemo1 2771 zfcndpow 4960 |
| This theorem was proved from axioms: ax-1 4 ax-2 5 ax-3 6 ax-mp 7 ax-7 960 ax-gen 961 ax-8 962 ax-10 964 ax-11 965 ax-12 966 ax-13 967 ax-14 968 ax-17 969 ax-4 971 ax-5o 973 ax-6o 976 ax-9o 1121 ax-10o 1138 ax-16 1208 ax-11o 1216 ax-ext 1457 ax-sep 2699 ax-nul 2706 ax-pow 2738 |
| This theorem depends on definitions: df-bi 147 df-or 224 df-an 225 df-ex 979 df-sb 1170 df-eu 1380 df-mo 1381 df-clab 1462 df-cleq 1467 df-clel 1470 df-ne 1584 df-v 1808 df-dif 2045 df-un 2046 df-in 2047 df-ss 2049 df-nul 2277 df-pw 2398 df-sn 2408 df-pr 2409 |